1. Question Mark: 2

7
6
5
2

2. Question Mark: 4

$(- \infty, 0) \cup (0, 1) \cup (1, \infty)$ $(- \infty, 0) \cup (0, 1) \cup (1, \infty)$
$(- \infty, 0) \cup (1, \infty)$ $(- \infty, 0) \cup (1, \infty)$
$(- \infty, 1) \cup (1, \infty)$ $(- \infty, 1) \cup (1, \infty)$
$(- \infty, - 1) \cup (1, \infty)$ $(- \infty, - 1) \cup (1, \infty)$

3. Question Mark: 6

ANSWER SHEET. Enter your answer below

4. Question Mark: 4

$x_{1} = - 5, x_{2} = \frac{1}{2}$ $x_{1} = - 5, x_{2} = \frac{1}{2}$
$x_{1} = 5, x_{2} = - \frac{1}{2}$ $x_{1} = 5, x_{2} = - \frac{1}{2}$
$x_{1} = - 3, x_{2} = 2$ $x_{1} = - 3, x_{2} = 2$
$x_{1} = - 5, x_{2} = - \frac{1}{2}$ $x_{1} = - 5, x_{2} = - \frac{1}{2}$

5. Question Mark: 6

ANSWER SHEET. Enter your answer below

6. Question Mark: 2

$\frac{1}{8}$ $\frac{1}{8}$
$\frac{1}{4}$ $\frac{1}{4}$
$- \frac{1}{8}$ $- \frac{1}{8}$
$- \frac{1}{2}$ $- \frac{1}{2}$

7. Question Mark: 4

$r = 4, b_{7} = 64$ $r = 4, b_{7} = 64$
$r = 2, b_{7} = 128$ $r = 2, b_{7} = 128$
$r = 4, b_{7} = 128$ $r = 4, b_{7} = 128$
$r = 4, b_{7} = 256$ $r = 4, b_{7} = 256$

8. Question Mark: 4

$a = 6, b = 6$ $a = 6, b = 6$
$a = 6, b = 6 \sqrt{3}$ $a = 6, b = 6 \sqrt{3}$
$a = 6, b = 8$ $a = 6, b = 8$
$a = 6 \sqrt{3}, b = 8$ $a = 6 \sqrt{3}, b = 8$

9. Question Mark: 2

6, 6, 12
8, 10, 12
5, 12, 13
10, 12, 15

10. Question Mark: 4

$x = 6, y = 5$ $x = 6, y = 5$
$x = 6, y = - 2$ $x = 6, y = - 2$
$x = 6, y = - 1$ $x = 6, y = - 1$
$x = - 6, y = 1$ $x = - 6, y = 1$

11. Question Mark: 4

$1$ $1$
$0$ $0$
$\frac{1}{1 - a}$ $\frac{1}{1 - a}$
$\frac{2}{a^{3} - 1}$ $\frac{2}{a^{3} - 1}$

12. Question Mark: 2

17
13
12
15

13. Question Mark: 2

$x^{2} - 2 x + 5 = 0$ $x^{2} - 2 x + 5 = 0$
$x^{2} + 2 x + 5 = 0$ $x^{2} + 2 x + 5 = 0$
$x^{2} - 3 x + 10 = 0$ $x^{2} - 3 x + 10 = 0$
$x^{2} + 3 x - 10 = 0$ $x^{2} + 3 x - 10 = 0$

14. Question Mark: 4

$x = \frac{8}{7}$ $x = \frac{8}{7}$
$x = \frac{7}{8}$ $x = \frac{7}{8}$
$x = 8$ $x = 8$
$x = 9$ $x = 9$

15. Question Mark: 4

9.22
10.44
19.66
18.87

16. Question Mark: 2

$\frac{c \sqrt{a} - \sqrt{b}}{a + b}$ $\frac{c \sqrt{a} - \sqrt{b}}{a + b}$
$\frac{\sqrt{a} - \sqrt{b}}{a - b}$ $\frac{\sqrt{a} - \sqrt{b}}{a - b}$
$\frac{c (\sqrt{a} - \sqrt{b})}{a + b}$ $\frac{c (\sqrt{a} - \sqrt{b})}{a + b}$
$\frac{c (\sqrt{a} - \sqrt{b})}{a - b}$ $\frac{c (\sqrt{a} - \sqrt{b})}{a - b}$

17. Question Mark: 8

ANSWER SHEET. Enter your answer below

18. Question Mark: 2

12
15
4
10

19. Question Mark: 2

1
$\frac{\sqrt{3}}{2}$ $\frac{\sqrt{3}}{2}$
$\frac{\sqrt{6} - \sqrt{2}}{4}$ $\frac{\sqrt{6} - \sqrt{2}}{4}$
$\frac{\sqrt{3} - \sqrt{2}}{2}$ $\frac{\sqrt{3} - \sqrt{2}}{2}$

20. Question Mark: 2

$\frac{1}{x - 3} - \frac{2}{x + 3}$ $\frac{1}{x - 3} - \frac{2}{x + 3}$
$\frac{2}{x - 3} - \frac{2}{x + 3}$ $\frac{2}{x - 3} - \frac{2}{x + 3}$
$\frac{2}{x - 3} - \frac{2}{x - 3}$ $\frac{2}{x - 3} - \frac{2}{x - 3}$
$\frac{1}{x + 3} - \frac{2}{x + 3}$ $\frac{1}{x + 3} - \frac{2}{x + 3}$

Mock Math Exam Practice Section.

7

6

5

2

(−∞, 0)∪(1, ∞)-∞, 0∪(1, ∞) <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mrow><mo>-</mo><mo>∞</mo><mo>,</mo><mo> </mo><mn>0</mn></mrow></mfenced><mo>∪</mo><mo>(</mo><mn>1</mn><mo>,</mo><mo> </mo><mo>∞</mo><mo>)</mo></math>

(−∞, 1)∪(1, ∞)-∞, 1∪(1, ∞) <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mrow><mo>-</mo><mo>∞</mo><mo>,</mo><mo> </mo><mn>1</mn></mrow></mfenced><mo>∪</mo><mo>(</mo><mn>1</mn><mo>,</mo><mo> </mo><mo>∞</mo><mo>)</mo></math>

(−∞, −1)∪(1, ∞)-∞, -1∪(1, ∞) <math xmlns="http://www.w3.org/1998/Math/MathML"><mfenced><mrow><mo>-</mo><mo>∞</mo><mo>,</mo><mo> </mo><mo>-</mo><mn>1</mn></mrow></mfenced><mo>∪</mo><mo>(</mo><mn>1</mn><mo>,</mo><mo> </mo><mo>∞</mo><mo>)</mo></math>

x1=−5, x2=12x1=-5, x2=12 <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>x</mi><mn>1</mn></msub><mo>=</mo><mo>-</mo><mn>5</mn><mo>,</mo><mo> </mo><msub><mi>x</mi><mn>2</mn></msub><mo>=</mo><mfrac><mn>1</mn><mn>2</mn></mfrac></math>

x1=5, x2=−12x1=5, x2=-12 <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>x</mi><mn>1</mn></msub><mo>=</mo><mn>5</mn><mo>,</mo><mo> </mo><msub><mi>x</mi><mn>2</mn></msub><mo>=</mo><mo>-</mo><mfrac><mn>1</mn><mn>2</mn></mfrac></math>

x1=−3, x2=2x1=-3, x2=2 <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>x</mi><mn>1</mn></msub><mo>=</mo><mo>-</mo><mn>3</mn><mo>,</mo><mo> </mo><msub><mi>x</mi><mn>2</mn></msub><mo>=</mo><mn>2</mn></math>

x1=−5, x2=−12x1=-5, x2=-12 <math xmlns="http://www.w3.org/1998/Math/MathML"><msub><mi>x</mi><mn>1</mn></msub><mo>=</mo><mo>-</mo><mn>5</mn><mo>,</mo><mo> </mo><msub><mi>x</mi><mn>2</mn></msub><mo>=</mo><mo>-</mo><mfrac><mn>1</mn><mn>2</mn></mfrac></math>

1818 <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mn>8</mn></mfrac></math>

1414 <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mn>4</mn></mfrac></math>

−18-18 <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>-</mo><mfrac><mn>1</mn><mn>8</mn></mfrac></math>

−12-12 <math xmlns="http://www.w3.org/1998/Math/MathML"><mo>-</mo><mfrac><mn>1</mn><mn>2</mn></mfrac></math>

r=4, b7=64r=4, b7=64 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>r</mi><mo>=</mo><mn>4</mn><mo>,</mo><mo> </mo><msub><mi>b</mi><mn>7</mn></msub><mo>=</mo><mn>64</mn></math>

r=2, b7=128r=2, b7=128 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>r</mi><mo>=</mo><mn>2</mn><mo>,</mo><mo> </mo><msub><mi>b</mi><mn>7</mn></msub><mo>=</mo><mn>128</mn></math>

r=4, b7=128r=4, b7=128 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>r</mi><mo>=</mo><mn>4</mn><mo>,</mo><mo> </mo><msub><mi>b</mi><mn>7</mn></msub><mo>=</mo><mn>128</mn></math>

r=4, b7=256r=4, b7=256 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>r</mi><mo>=</mo><mn>4</mn><mo>,</mo><mo> </mo><msub><mi>b</mi><mn>7</mn></msub><mo>=</mo><mn>256</mn></math>

a=6, b=6a=6, b=6 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>a</mi><mo>=</mo><mn>6</mn><mo>,</mo><mo> </mo><mi>b</mi><mo>=</mo><mn>6</mn></math>

a=6, b=63–√a=6, b=63 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>a</mi><mo>=</mo><mn>6</mn><mo>,</mo><mo> </mo><mi>b</mi><mo>=</mo><mn>6</mn><msqrt><mn>3</mn></msqrt></math>

a=6, b=8a=6, b=8 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>a</mi><mo>=</mo><mn>6</mn><mo>,</mo><mo> </mo><mi>b</mi><mo>=</mo><mn>8</mn></math>

a=63–√, b=8a=63, b=8 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>a</mi><mo>=</mo><mn>6</mn><msqrt><mn>3</mn></msqrt><mo>,</mo><mo> </mo><mi>b</mi><mo>=</mo><mn>8</mn></math>

6, 6, 12

8, 10, 12

5, 12, 13

10, 12, 15

x=6, y=5x=6, y=5 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>x</mi><mo>=</mo><mn>6</mn><mo>,</mo><mo> </mo><mi>y</mi><mo>=</mo><mn>5</mn></math>

x=6, y=−2x=6, y=-2 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>x</mi><mo>=</mo><mn>6</mn><mo>,</mo><mo> </mo><mi>y</mi><mo>=</mo><mo>-</mo><mn>2</mn></math>

x=6, y=−1x=6, y=-1 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>x</mi><mo>=</mo><mn>6</mn><mo>,</mo><mo> </mo><mi>y</mi><mo>=</mo><mo>-</mo><mn>1</mn></math>

x=−6, y=1x=-6, y=1 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>x</mi><mo>=</mo><mo>-</mo><mn>6</mn><mo>,</mo><mo> </mo><mi>y</mi><mo>=</mo><mn>1</mn></math>

11 <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>1</mn></math>

00 <math xmlns="http://www.w3.org/1998/Math/MathML"><mn>0</mn></math>

11−a11-a <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mrow><mn>1</mn><mo>-</mo><mi>a</mi></mrow></mfrac></math>

2a3−12a3-1 <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>2</mn><mrow><msup><mi>a</mi><mn>3</mn></msup><mo>-</mo><mn>1</mn></mrow></mfrac></math>

17

13

12

15

x2−2x+5=0x2-2x+5=0 <math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>2</mn><mi>x</mi><mo>+</mo><mn>5</mn><mo>=</mo><mn>0</mn></math>

x2+2x+5=0x2+2x+5=0 <math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo><mn>2</mn><mi>x</mi><mo>+</mo><mn>5</mn><mo>=</mo><mn>0</mn></math>

x2−3x+10=0x2-3x+10=0 <math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mi>x</mi><mn>2</mn></msup><mo>-</mo><mn>3</mn><mi>x</mi><mo>+</mo><mn>10</mn><mo>=</mo><mn>0</mn></math>

x2+3x−10=0x2+3x-10=0 <math xmlns="http://www.w3.org/1998/Math/MathML"><msup><mi>x</mi><mn>2</mn></msup><mo>+</mo><mn>3</mn><mi>x</mi><mo>-</mo><mn>10</mn><mo>=</mo><mn>0</mn></math>

x=87x=87 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>x</mi><mo>=</mo><mfrac><mn>8</mn><mn>7</mn></mfrac></math>

x=78x=78 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>x</mi><mo>=</mo><mfrac><mn>7</mn><mn>8</mn></mfrac></math>

x=8x=8 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>x</mi><mo>=</mo><mn>8</mn></math>

x=9x=9 <math xmlns="http://www.w3.org/1998/Math/MathML"><mi>x</mi><mo>=</mo><mn>9</mn></math>

9.22

10.44

19.66

18.87

ca√−b√a+bca-ba+b <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mi>c</mi><msqrt><mi>a</mi></msqrt><mo>-</mo><msqrt><mi>b</mi></msqrt></mrow><mrow><mi>a</mi><mo>+</mo><mi>b</mi></mrow></mfrac></math>

a√−b√a−ba-ba-b <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><msqrt><mi>a</mi></msqrt><mo>-</mo><msqrt><mi>b</mi></msqrt></mrow><mrow><mi>a</mi><mo>-</mo><mi>b</mi></mrow></mfrac></math>

c(a√−b√)a+bc(a-b)a+b <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mi>c</mi><mo>(</mo><msqrt><mi>a</mi></msqrt><mo>-</mo><msqrt><mi>b</mi></msqrt><mo>)</mo></mrow><mrow><mi>a</mi><mo>+</mo><mi>b</mi></mrow></mfrac></math>

c(a√−b√)a−bc(a-b)a-b <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><mi>c</mi><mo>(</mo><msqrt><mi>a</mi></msqrt><mo>-</mo><msqrt><mi>b</mi></msqrt><mo>)</mo></mrow><mrow><mi>a</mi><mo>-</mo><mi>b</mi></mrow></mfrac></math>

12

15

4

10

1

3√232 <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><msqrt><mn>3</mn></msqrt><mn>2</mn></mfrac></math>

6√−2√46-24 <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><msqrt><mn>6</mn></msqrt><mo>-</mo><msqrt><mn>2</mn></msqrt></mrow><mn>4</mn></mfrac></math>

3√−2√23-22 <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mrow><msqrt><mn>3</mn></msqrt><mo>-</mo><msqrt><mn>2</mn></msqrt></mrow><mn>2</mn></mfrac></math>

1x−3−2x+31x-3-2x+3 <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mrow><mi>x</mi><mo>-</mo><mn>3</mn></mrow></mfrac><mo>-</mo><mfrac><mn>2</mn><mrow><mi>x</mi><mo>+</mo><mn>3</mn></mrow></mfrac></math>

2x−3−2x+32x-3-2x+3 <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>2</mn><mrow><mi>x</mi><mo>-</mo><mn>3</mn></mrow></mfrac><mo>-</mo><mfrac><mn>2</mn><mrow><mi>x</mi><mo>+</mo><mn>3</mn></mrow></mfrac></math>

2x−3−2x−32x-3-2x-3 <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>2</mn><mrow><mi>x</mi><mo>-</mo><mn>3</mn></mrow></mfrac><mo>-</mo><mfrac><mn>2</mn><mrow><mi>x</mi><mo>-</mo><mn>3</mn></mrow></mfrac></math>

1x+3−2x+31x+3-2x+3 <math xmlns="http://www.w3.org/1998/Math/MathML"><mfrac><mn>1</mn><mrow><mi>x</mi><mo>+</mo><mn>3</mn></mrow></mfrac><mo>-</mo><mfrac><mn>2</mn><mrow><mi>x</mi><mo>+</mo><mn>3</mn></mrow></mfrac></math>

Applicant Full Name

$(- \infty, 0) \cup (1, \infty)$ $(- \infty, 0) \cup (1, \infty)$

$(- \infty, 1) \cup (1, \infty)$ $(- \infty, 1) \cup (1, \infty)$

$(- \infty, - 1) \cup (1, \infty)$ $(- \infty, - 1) \cup (1, \infty)$

$x_{1} = - 5, x_{2} = \frac{1}{2}$ $x_{1} = - 5, x_{2} = \frac{1}{2}$

$x_{1} = 5, x_{2} = - \frac{1}{2}$ $x_{1} = 5, x_{2} = - \frac{1}{2}$

$x_{1} = - 3, x_{2} = 2$ $x_{1} = - 3, x_{2} = 2$

$x_{1} = - 5, x_{2} = - \frac{1}{2}$ $x_{1} = - 5, x_{2} = - \frac{1}{2}$

$\frac{1}{8}$ $\frac{1}{8}$

$\frac{1}{4}$ $\frac{1}{4}$

$- \frac{1}{8}$ $- \frac{1}{8}$

$- \frac{1}{2}$ $- \frac{1}{2}$

$r = 4, b_{7} = 64$ $r = 4, b_{7} = 64$

$r = 2, b_{7} = 128$ $r = 2, b_{7} = 128$

$r = 4, b_{7} = 128$ $r = 4, b_{7} = 128$

$r = 4, b_{7} = 256$ $r = 4, b_{7} = 256$

$a = 6, b = 6$ $a = 6, b = 6$

$a = 6, b = 6 \sqrt{3}$ $a = 6, b = 6 \sqrt{3}$

$a = 6, b = 8$ $a = 6, b = 8$

$a = 6 \sqrt{3}, b = 8$ $a = 6 \sqrt{3}, b = 8$

$x = 6, y = 5$ $x = 6, y = 5$

$x = 6, y = - 2$ $x = 6, y = - 2$

$x = 6, y = - 1$ $x = 6, y = - 1$

$x = - 6, y = 1$ $x = - 6, y = 1$

$1$ $1$

$0$ $0$

$\frac{1}{1 - a}$ $\frac{1}{1 - a}$

$\frac{2}{a^{3} - 1}$ $\frac{2}{a^{3} - 1}$

$x^{2} - 2 x + 5 = 0$ $x^{2} - 2 x + 5 = 0$

$x^{2} + 2 x + 5 = 0$ $x^{2} + 2 x + 5 = 0$

$x^{2} - 3 x + 10 = 0$ $x^{2} - 3 x + 10 = 0$

$x^{2} + 3 x - 10 = 0$ $x^{2} + 3 x - 10 = 0$

$x = \frac{8}{7}$ $x = \frac{8}{7}$

$x = \frac{7}{8}$ $x = \frac{7}{8}$

$x = 8$ $x = 8$

$x = 9$ $x = 9$

$\frac{c \sqrt{a} - \sqrt{b}}{a + b}$ $\frac{c \sqrt{a} - \sqrt{b}}{a + b}$

$\frac{\sqrt{a} - \sqrt{b}}{a - b}$ $\frac{\sqrt{a} - \sqrt{b}}{a - b}$

$\frac{c (\sqrt{a} - \sqrt{b})}{a + b}$ $\frac{c (\sqrt{a} - \sqrt{b})}{a + b}$

$\frac{c (\sqrt{a} - \sqrt{b})}{a - b}$ $\frac{c (\sqrt{a} - \sqrt{b})}{a - b}$

$\frac{\sqrt{3}}{2}$ $\frac{\sqrt{3}}{2}$

$\frac{\sqrt{6} - \sqrt{2}}{4}$ $\frac{\sqrt{6} - \sqrt{2}}{4}$

$\frac{\sqrt{3} - \sqrt{2}}{2}$ $\frac{\sqrt{3} - \sqrt{2}}{2}$

$\frac{1}{x - 3} - \frac{2}{x + 3}$ $\frac{1}{x - 3} - \frac{2}{x + 3}$

$\frac{2}{x - 3} - \frac{2}{x + 3}$ $\frac{2}{x - 3} - \frac{2}{x + 3}$

$\frac{2}{x - 3} - \frac{2}{x - 3}$ $\frac{2}{x - 3} - \frac{2}{x - 3}$

$\frac{1}{x + 3} - \frac{2}{x + 3}$ $\frac{1}{x + 3} - \frac{2}{x + 3}$